Simplify 5 1 3 2

Simplify the post-obit:
$ viii \frac{iii}{5}-\left(6 \frac{1}{2}-four \frac{ane}{4}-iii \frac{3}{four}\right) $

Given: $8\frac{3}{5} \ -\ \left( 6\frac{1}{2} \ -\ four\frac{1}{4} \ -\ 3\frac{iii}{4}\right)$To discover: Hither we have to observe the value of $8\frac{three}{5} \ -\ \left( half-dozen\frac{1}{ii} \ -\ four\frac{1}{4} \ -\ 3\frac{3}{four}\right)$.Solution:$8\frac{3}{5} \ -\ \left( 6\frac{1}{two} \ -\ 4\frac{one}{iv} \ -\ iii\frac{3}{iv}\right)$$=\ \frac{43}{five} \ -\ \left(\frac{xiii}{ii} \ -\ \frac{17}{iv} \ -\ \frac{fifteen}{4}\right)$ $=\ \frac{43}{5} \ -\ \left(\frac{thirteen}{2} \ -\ \frac{32}{4}\right)$$=\ \frac{43}{five} \ -\ \left(\frac{26\ -\ 32}{four}\correct)$$=\ \frac{43}{5} \ -\ \left( -\ \frac{six}{4}\right)$$=\ \frac{43}{5} \ -\ \left( -\ \frac{three}{ii}\right)$$=\ \frac{43}{5} \ +\ \frac{3}{two}$$=\ \frac{86\ +\ 15}{10}$$=\ \mathbf{\frac{101}{10}}$So, the answer is $\frac{101}{10}$.

Updated on 10-Oct-2022 x:19:06

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